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(1ai -1aiv)
S/N|M(g)|Real values of b(cm)|Converted values of b(cm)| Real Value of d(cm)| Converted values of d(cm)| N = b/d
1 |20 |5.30|26.50|12.9|64.5|0.41|
2 |40 |8.0 |40.0 |10 |50.0|0.80|
3 |60 |9.9 |49.5 |8.3|41.5|1.20|
4 |80 |11.0|55.0 |7.0|35.0|1.50|
5 |100|12.1|60.5 |6.0|30.0|2.0|

(1bi)
(i)the total upward force must balance the downword
(ii) the algebraic sum of all forces act on the body must be equal to zero

(1bii)
If sum of moments of all forces must be zero
.:. 20g x 45cm = 100g x Xcm
X = 20g c 45cm / 100g
= (900/100)
= 9cm

(1bii)

(1vi)
slope = Y2-Y1/x2-x1
=70-20/1.4-0.4
= 50/1
=50g

(1vi)
(i) I avoid error due to parallel when taking all my reading
(ii)I made sure that the meter rule beconect horizontally before taking my reading

(1a)

(1)
Graph

(3ai -3aiv)
S/N|R(ohms)|V(v)|I(A)|1/v(A/v)|R-¹(ohm-¹)|
1 | 1.0|1.21|1.80|1.49|1.00
2 | 2.0|1.50|1.50|1.00|0.50
3 | 3.0|1.64|1.36|0.83|0.33
4 | 4.0|1.72|1.29|0.75|0.25
5 | 5.0|1.76|1.23|0.70|0.20

(3av)
PLOT THE GRAPH

(3avi)
Slope = Î”A/V / Î”R-¹
= 1.28 - 0.80/ 0.80 - 0.30
= 0.48/0.50
= 0.96

Intercept (c) = 0.50

(3avii)
(i) I would ensure I made tight connection before taking my reading.
(ii) I would ensure I noted zero error on the voltmeter and Ammeter

(3bi)
Potential difference is the work done in moving a unit charge from a point in electric field to another. It has the unit of Volt.
V = work done/charge

(3bii)
r = 0.5ohms
I = 1.2A
R = ?
E = 3v
E = I(R+r)
E = IR + Ir
E - Ir = IR
R = E - Ir/I
= 3 - 1.2 Ã— 0.5/1 .2
= 3 - 0.6/1.2
R = 2.4/1.2
R = 2 ohms

(3a)

(3b)

(3)
GRAPH

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