2025/2025 WAEC/NECO Answers: 2025 Waec Gce. Agric practical answers

(4a)
I - Duct
II - Testis
III - Penis
VI - Seminal Viscule 
V - Penis coat
IV - Epididymis 

(4b) 
Duct: It moves the sperm cell from testis to penis. 
Testis: It helps to store the sperm cells or spermatozoa.
Penis: It is used to introduce the sperm cell into the female. 
Seminal Viscule: It helps to form a fluid in which the sperm cells can move. 
Penis coat: It protects the penis 
Epididymis: It transports and stores sperm cells that are produced in the testes

(4ci)
Castration

(4cii)
(i) Duct will be cut. 
(ii) The epididymis will be removed.

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(3a)
I - Grasshopper 
II - Weevil 
III - Cotton stainer

(3b)
I - Grasshopper exhibits incomplete metamorphosis that is Egg-nymph-adult

(3c)
(i) Transmission of diseases which are harmful to crops. 
(ii) It means to stunted growth of plants. 
(iii) It leads to yellowing of leaves due to the absence of micro nutrients like phosphorous
(iv) It leads to death of plants

(3d)
(i) Setting traps like funnel entrance traps with trigger mechanism
(ii) Use of avicides
(iii) Use of fenced traps
(iv) Use of poison baits

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(2a)
Area of farmland = 1/2(70+90)40
=1/2(160)×40
80×40=3200m²

(2b) 
The spacing will take an area of 4×4 = 16cm²
The number of banana plants in the farmland =
Total area of farmland/Area taken by each banana 
=3200m²/16m²
=200

(2ci)
I - Raging pole
II - Survey Pin 

(2cii)
Uses of I:
(i) For mark out area to be measured
(ii) It guides the surveyor

Uses of II:
(i) For marking out chain length as measured
(ii) For making out areas that are not straight

(2ciii)
(i) Rub oil on the metal surface before storage
(ii) Store in a dry place

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(1a) 
To determine the water content of the soil sample. 

(1b) 
I - Crucible. 
II - Soil sample. 
III - Retort stand 
IV - Bunsen burner 

(1ci)
Water of dry sand = weight of sand and container - weight of container
= 80g - 35g
= 45g

(1cii)
Weight of water lost = original weight of sand and container - final weight 
= 95g - 80g
=15g

(1ciii)
Percentage of water lost 
= 15/80 x 100/1 
= 18.75%

(1d)
(i) Capillary water
(ii) Hygroscopic water
(iii) Gravitational water

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