(9a)
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(9c)
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(8a)
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(8b)
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(3a)
Given : R(3,5) and S(-2, -6)
equation to line through them is :
y-5/x-3 = -6-5/-2-3
y-5/x-3 = -11/-5
y-5/x-3 = 11/5
5(y-5)= 11(x-3)
5y-25 = 11x-33
5y-11x = 25-33
5y-11x = -8 or 11x-5y = 8
(3b)
RS= √(X1X2)^2 (y1y2)^2
√(-2-3)^2 + (-6-5)^2
√(-5)^2 + (-11)^2
√25 + 121
√146
= 12.08
(3)
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(4a)
Given: curve; y x^2 - 3x
gradient ; dy/dx = 2x - 3
At (2-2), gradient = 2(2) - 3
4-3 = 1
(4b)
Given; y= 1+x^2/1-x^-2
dy/dx = (1-x^2)(2x) - (1+x^2)(-2x)/(1-x^2)^2
= (1-x^2)(2x) - (1+x^2)(2x)/(1-x^2)^2
= 2x(1-x^2 + 1+x^2)/(1-x^2)^2
= 2x(2)/(1-x^2)^2
= 4x/(1-x^2)^2
(4)
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(1)
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(2)
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(7)
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