2024 NECO GCE PHYSICS: 2024 NECO GCE ANSWERS. PHYSICS PRACTICAL (7118)

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Welcome to official 2024 Physics NECO GCE answer page. We provide 2024 Physics NECO GCE Questions and Answers on Essay, Theory, OBJ midnight before the exam, this is verified & correct NECO GCE Phy Expo. NECO GCE Physics Questions and Answers 2024. NECO GCE Phy Expo for Theory & Objective (OBJ) PDF: verified & correct expo Solved Solutions, 2024 NECO GCE ANSWERS. PHYSICS PRACTICAL . 2024 NECO GCE EXAM Physics Questions and Answers

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(3a)

In a tabular form 

Under S/N

1, 2, 3, 4, 5, 6


Under R(ohms)

5.0, 10.0, 15.0, 20.0, 25.0, 30.0


Under X(cm)

33.00, 49.50, 60.00, 67.00, 71.00, 74.50


Under K = 100 -X(cm)

67.00, 50.50, 40.00, 33.00, 29.00, 25.50


Under Y = x/k

0.4925, 0.9802, 1.5000, 2.0303, 2.4483, 2.9216


(3avi)

DRAW THE GRAPH


2024 NECO GCE ANSWERS. PHYSICS PRACTICAL  2024 NECO GCE PHYSICS: 2024 NECO GCE ANSWERS. PHYSICS PRACTICAL  (7118) Welcome to official 2024 Physics NECO GCE answer page. We provide 2024 Physics NECO GCE Questions and Answers on Essay, Theory, OBJ midnight before the exam, this is verified & correct NECO GCE Phy Expo


(3avii)

Slope 

R2 - R1/y2 -y1

= 20 - 5/2.0 - 0.5

= 15/1.5

=10.0 ohms


(3aviii)

(i) I must use a freshly charged accumulator. 

(ii) I must take proper readings through my resistance box and potentiometer to avoid error due to parallax


(3bi)

Lost volt is the voltage lost due to the internal resistance of a cell.  It is measured in volts. 


(3bii)

E = I(R+r)

4 = I(2+0.5)

4 = 2.5I

I = 4/2.5

= 1.6A

======================================

(1aiv)

In a tabular form

Under S/N

1.0, 2.0, 3.0, 4.0, 5.0


Under y(g)

8.00, 10.00, 12.00, 14.00, 16.00


[Under yR(g)= 12.5*y]

100.00, 125.00, 150.00, 175.00, 200.00


Under X(cm)

17.60, 14.00, 11.60, 10.00, 8.70


Under XR(cm) = x * 2

35.00, 28.00, 23.20, 20.00, 17.40


Under L = 70/X

2.000, 2.500, 3.000, 3.500, 4.00


DRAW ANOTHER TABLE OF y(g) and L(cm)

Under y(g)

100.00

125.00

150.00

175.00

200.00


Under L(cm)

2.00

2.50

3.00

3.50

4.00


(1av)

DRAW THE GRAPH


(1avi)

Slope(s) = Dy/DL =

y2 - y1/L2 - L1

Where y2 = 175g, y1 = 100g

L2 = 3.5cm, L1 = 2.00cm


Slope(s) = 175 - 100/3.5 - 2


(1avii)

(i)I ensured mass did not touch/rest on the table

(ii)I avoided error due to parallax on metre rule

(iii)I noted zero error on metre rule

(iv)I avoided draught


(1bi)

The principal of moments state that if a body is in equilibrium,then the sum of the clockwise moments about any point on the body is equal to the sum of the anticlockwise moments about the same point


(1bii)

Draw the diagram 


Taking moments about point B ie CWM = ACM

(FA*7) = 10*2

7F = 20

7F/7 = 20/7

F = 2.9N

= 75/1.5

= 50g/cm

======================================


2bi) I Rainbow 

       II Wave length


2v)

​SLOPE​


Slope,s =y2-y1/x2-x1

              =56.7-20/4-1


              =36.7/3


              =12.233


              =12.23


2vi)U = 100/S = 100/12.23 

= 8.176


=8.18


2vii)

– I will avoid error due to parallax while reading the meter rule.

-I will ensure the mass is kept dried before weighing


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